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纬度英文:有用的小学到初中所有数学公式大全

作者:高考题库网
来源:https://www.bjmy2z.cn/gaokao
2020-11-11 22:45
tags:数学的公式小学到初中

向量公式-大连外国语大学2017录取分数线

2020年11月11日发(作者:仲崇祜)
有用的小学到初中所有数学公式大全(Useful mathematics from
elementary school to junior middle school)
1, the number of copies of each number x = total number, each
number of copies, copies number = = each number

2, 1 times of a few a few multiples of multiples of multiples
of x = 1, = several multiples of multiples of multiples of
multiples = 1 times

3, speed time distance, distance = x = distance time time speed
= speed

4, the number of the total price, price x = = = the number of
total number of unit price, unit price

5, work efficiency * working time = total amount, total work
efficiency = working time

The total amount of work, work time = work efficiency

6, the addend addend = + and - addend = other addend

7, the minuend - = = - difference difference reduction minuend
difference + = minuend meiosis meiosis

8, factor X factor = product divided by a factor = another factor

9, dividend, dividend, divisor = business taking = x = dividend
dividend divisor quotient

Mathematical formulas for elementary school mathematics

1, square: C perimeter, S area, a length side length = perimeter
= 4C=4a area = length side * S=a * a

2, the cube: V: volume a: edge length surface area = length x
length x 6 S =a * a * 6

Volume = edge length x x long * x V=a x a * a

3, rectangle:

C perimeter, S area, a, side length, perimeter = (length + width)
* 2 C=2 (a+b) area = * * width S=ab

4, cuboid

V: volume s:, area a: long, b: width, h: height

(1) surface area (length * width + length * height + width *
height) * 2 S=2 (ab+ah+bh)

(2) volume = long * width * high V=abh

5, triangle

S a h high end area bottom area = x height 2 s=ah 2

Triangle area high = x 2 bottom

Triangle area = x 2 high

6, parallelogram: s area a, bottom h, high area = bottom * high
s=ah

7, ladder: s area a b h high bottom bottom area = (+ down on
the bottom end) * 2 s= (a+b) * H 2

8 round: S C d= r= diameter radius circumference pi

(1) = =2 * * * perimeter diameter radius C= d=2 pi pi pi * r

(2) * * * area = radius radius

9, cylinder: V, volume h:, high S: bottom area R: bottom radius
C: bottom perimeter

(1) the side area = the circumference of the bottom * high

(2) surface area = side area + base area * 2

(3) volume = base area * height

(4) = 2 X volume side area radius

10, V: h s high volume cone bottom area R bottom radius size
= base area x height 3

The total, the total number of copies = average number

Equation of sum and difference

(+ and difference) 83019 2 = number

(and poor) 83019 2 = decimal

Doubling problem

And (1 = decimal multiples).

Decimal = multiple = large number

(or sum = decimal = large number)

Difference problem

(1 difference multiples) = decimal

Decimal = multiple = large number

(or decimal + difference = large number)

Tree planting problem

1, the problem of tree planting on non closed lines can be
divided into the following three cases:

If a non closed line at both ends are planting trees, so:

Number = number of + 1 1 = length spacing

* (1 = length spacing number)

Full length (1 spacing = number)

If you want to plant trees in the end of non closed line, the
other end is not planting, so:

Number = number = length spacing

Length = x number of rows

= length number of rows

If both ends in non closed line are not planting trees, so:

Number section number = - 1 1 = length spacing

* (number = length spacing + 1)

= length spacing (number 1)

2, the number of trees on closed lines is as follows

Number = number = length spacing

Length = x number of rows

= length number of rows

Profit and loss

(profit + loss), the two distribution of the difference between
the number of copies in the distribution of =

(large surplus - small surplus) two distribution of the
difference between the number of copies in the distribution of
=

(burned - a small loss of two times), the difference between
the number of copies is assigned to participate in the
distribution of the

Encounter problem

Encounter distance = speed and X meeting time

Meet time = distance speed and meet

The speed and distance, the encounter time = meet

Catch up with problems

Tracking distance = speed difference * tracking time

Chase and chase and distance time = speed difference

The speed difference and distance = chase chase and time.

Flow problem

Downstream velocity = hydrostatic velocity + flow velocity

Countercurrent velocity = hydrostatic velocity - flow velocity

Hydrostatic speed = (downstream velocity and velocity), 2

Flow rate = (downstream speed velocity), 2

Concentration problem

The weight of the solute + the weight of the solvent = the weight
of the solution

The weight, the weight of the solute solution x 100% =
concentration

Weight of solution = concentration = solute weight

The weight, concentration of solute solution = weight

Profit and discount problems

Profit = selling price - cost

The rate of profit, profit = cost X 100% = (sold cost 1) *
100%

Amount of fluctuation = principal * Change Percentage

The actual price discount, the original price x = 100% (< 1
discount)

Interest = principal * interest rate * time

After tax interest rates * * * = principal time (120%)

Length Conversion

1 kilometers 1 meters =1000 meters =10.

1 cm =100 cm =10 1 meter decimeter

1 cm =10 mm

Area Conversion

1 sq km =100 hectares

1 hectares =10000 square meters

1 square meters =100 square decimeter

1 square =100 square centimeter decimeter

1 mm2 =100 mm2

Volume (volume) product unit conversion

1 cubic meters =1000 cubic decimeter

1 cubic meter =1000 cubic centimeter

1 DM3 =1 L

1 cubic centimeter =1 ml.

1 cubic meters =1000 liters

Weight unit conversion

1 tons =1000 kg

1 kilograms =1000 grams

1 kg =1 kg

Unit conversion of Renminbi

1 yuan =10 Jiao

1 jiao =10 minutes

1 yuan =100 cents

time conversion

First Century =100, 1 years =12 months

Month (31 days): 135781012 month

Xiaoyue (30 days) are: 46911 month

There are 28 days in February, a leap year 29 days in February

There are 365 days a year, a leap year 366 days a year

1 days =24 hours, 1 hours =60 minutes

1 minutes, =60 seconds, 1 hours, =3600 seconds

Mathematical formulas of geometry, perimeter, area and volume
of Primary Mathematics

1, the perimeter of the rectangle = (long + width) * 2 C= (a+b)
* 2

2, square perimeter = side length * 4 C=4a

3, rectangular area = long * width S=ab

4, square area = length side * side length S=a.a= a

5, the bottom of the triangle area = x height 2 S=ah 2

6. The area of the parallelogram = bottom * high S=ah

Area = 7, trapezoidal (bottom + bottom) x height 2 S= (a +
b) H 2

8 x 2 d=2r diameter = radius radius = 2 D 2 r= diameter.

9, the circumference of a circle diameter x = pi = pi * * 2 c=
D =2 radius Pi Pi R

10, the area of a circle radius radius = pi * *

Common formulas for junior high school mathematics

1 there is only one line after two

2 the line between two points is the shortest

3 the same angle or isometric equal margin

4 with the angle of the complement of equal or constant

5 having only one line and perpendicular to the known line

6, the line outside a point and the line on all points connected
by the line, the vertical line segment is the shortest

7 parallel axioms follow a point outside the straight line and
have only one line in parallel with the line

8 if the two lines are parallel to the third lines, the two lines
are parallel to each other

9 corresponding angles are equal, the two parallel lines

10 alternate angles are equal, the two parallel lines

11 complementary interior angles on the same side, two parallel
lines

12 the two parallel lines, corresponding angles are equal

13 two line parallel, alternate angles are equal

14 the two parallel lines, complementary interior angles on the
same side

The sum of 15 sides of a triangle is greater than third

16 infer that the difference between the sides of a triangle
is less than third

17 triangle triangle sum theorem three angles and equal to 180
degrees

18 inference 1 the two acute angles of right triangle overlap
each other

19 a corollary of a triangle is equal to the 2 corners and two
angles it is adjacent and

20 a corollary of a triangle with 3 corners than any one and
it is not adjacent.

The corresponding sides of 21 congruent triangles and equal
angles

22 edge axioms (SAS) are congruent with two triangles of equal
angles on both sides and their angles

23 corner corner axiom (ASA) has two triangles congruent horns
and their edges corresponding to the equal

24 inference (AAS) had two horns and one of the angle on the
side corresponding to the equal two congruent triangles

25 side axioms (SSS) having two equal triangles equal to three
sides

26 bevel and right side axioms (HL) have two equal angles of
right triangle and one right angle

Congruent

27 theorem 1 the distance between points on the bisector of an
angle to the sides of this angle is equal

The point at which the distance between 2 and 28 angles is the
same as in the bisector of this angle

The bisector of 29 angles is the set of all points equal to the
two sides of the angle

Two and 30 are equal isosceles triangle theorem of an isosceles
triangle (i.e. equal equilateral angle)

31 infer that the bisector of the 1 isosceles triangle vertex
is equal to the base and perpendicular to the base

32 the top angles of the isosceles triangle, the bisector, the
middle line on the bottom edge and the height on the bottom edge
coincide with each other

33 corollary 3 equilateral triangles whose angles are equal,
and each angle equal to 60 degrees

34 the decision theorem of isosceles triangle, if a triangle
has two angles equal, then these two angles

The opposite sides are equal (equal angles, equal sides)

35 corollary 1 three angles are equal triangle is an equilateral
triangle

36 corollary 2 an isosceles triangle with an angle equal to 60
degrees is an equilateral triangle

37 in a right triangle, if an acute angle is equal to 30 degrees,
the right angled edge of it is equal to the beveled edge

half

38 the center line on the bevel of a right triangle is equal
to half of the bevel

The point at which the two ends of the line of the line of
division are equal to the 39 ends of the line

A point equal to the distance between two endpoints of 40
inverse theorem and a line segment, in the vertical bisector
of the line

The vertical bisector of a 41 line segment can be considered
as a set of all points equal to the distance between points at
the end of a line segment

42 theorem 1 the two graphs of a straight line symmetry are
congruent forms

43 theorem 2 if two graphs are symmetrical about a straight line,
then the symmetry axis is perpendicular to the line of the
corresponding point

Bisector

44 theorems 3, two graphs are symmetrical about a line, if their
corresponding lines or extension lines intersect,

Then the intersection point is on the symmetry axis

The 45 inverse theorem, if the corresponding lines of the two
graphs are vertically divided by the same line, then two

A graph relating to the symmetry of a line

46 Pythagorean theorem of right triangle two right angle sides
a, b square, and is equal to the square of the hypotenuse c,

That is, a^2+b^2=c^2

47 the Pythagorean theorem and inverse theorem of a, if the
three side of triangle B, C a^2+b^2=c^2,

Then the triangle is right angled triangle

In theorem 48 quadrilateral and equal to 360 degrees

49 quadrilateral corners and is equal to 360 degrees

In the 50 polygon sum theorem n edge shape and is equal to (n-2)
* 180 degrees

51 any inference multilateral angle and equal to 360 degrees

The property theorem of 52 parallelogram; the diagonal equality
of 1 parallelogram

The property theorem of 53 parallelogram; the equal sides of
2 parallelogram

54 parallels between two parallel lines are equal

The property theorem of 55 parallelogram; diagonal bisector of
3 parallelogram

56 parallelogram decision theorem 1. The two groups of equal
angles are parallelogram

57 parallelogram decision theorem 2. The quadrilateral of two
sets of equal sides is parallelogram

The 58 parallelogram theorem; 3 diagonals equal to one another;
the quadrilateral is a parallelogram

59 the parallelogram theorem 4 is a parallelogram of parallel
pairs of edges equal to a parallelogram

Four angles of 60 rectangular theorem 1 rectangle is right

61 rectangular property theorem 2 the diagonal of a rectangle
is equal

62 rectangular decision theorem 1 has three angles at right
angles, and a quadrilateral is a rectangle

63 rectangular decision theorem 2 a parallelogram with equal
diagonals is a rectangle

64 diamond theorem 1 the four sides of a diamond are equal

65 diamond theorem 2 the diagonals of the diamond are
perpendicular to each other and each diagonal line is divided
into a set of diagonal angles

Half of the 66 diamond area = diagonal product, namely S= (a
* b) 2

67 diamond decision theorem 1 quadrilateral is equal to four
sides is diamond

68 diamond decision theorem 2 the diagonals are perpendicular
to each other and the parallelogram is rhombic

The 69 square theorem four angles of 1 square is a right angle.
The four sides are equal

70 the square theorem of 2 squares equal to two diagonals and
perpendicular to each other

A diagonal set of diagonal lines

The 71 theorem 1, about the central symmetry of the two graphs
are congruent

72 theorem 2 relating to the central symmetry of the two figures,
the symmetry points, the connection is through the center of
symmetry, and be

Symmetric central bisection

The 73 inverse theorem, if the corresponding points of the two
graphs are connected at a certain point and equal to this point,

Well, these two graphs are symmetrical about this point

74 isosceles trapezoid property theorem the isosceles
trapezoid is equal to two angles at the same bottom

75 isosceles trapezium with two diagonals equal

76 isosceles trapezoid judgment theorem, on the same bottom,
the two angles equal trapezoid is isosceles trapezoid

77 the trapezium with equal diagonals is isosceles trapezoid

A theorem of 78 parallel lines, if the line segments of a set
of parallel lines are equal in a straight line,

Then the line segment that is cut on the other line is equal

79 inference 1, after the ladder, the middle of a waist and the
bottom parallel line, will be equal to the other waist

80 inference 2 the line between the midpoint of the triangle
and the other side is equal to the third side

81 the median line of a triangle in which the median line of
a triangle is parallel to the third side and equal to half of
it

The median line theorem of the 82 ladder theorem. The median
line of a ladder is parallel to the bottom of the two and equal
to half of the sum of the two bases

L= (a+b) 2 S=L * h

83 (1) the basic nature of the ratio, if a:b=c:d, then ad=bc,
if ad=bc, then a:b=c:d

84 (2), if the ratio of a b=c D, then (a + b) b= (c + D)
D

85 (3) geometric properties, if a b=c d=... =m N (b+d+...
+n (a+c+ = 0), then... +m)

(b+d+... +n) =a b

86 parallel lines are divided into line segments, and three
parallel lines are cut into two straight lines

Proportion

87 inference parallel to the triangular side of the line,
cutting the other sides (or the extension line on both sides)

Proportional to line segments

The 88 theorem, if a line cuts the sides of a triangle (or the
extension lines on both sides), the corresponding lines

The line is parallel to the third side of the triangle

A triangle of 89 parallel to one side of a triangle and
intersecting with the other sides

The three side is proportional to the three sides of the
original triangle

90 theorems parallel to one side of a triangle, intersecting
with the other sides (or extended lines on both sides),

The triangle formed is similar to the original triangle

91 similar triangles theorem 1 corners equal two triangles
(ASA)

92 right angled triangles are divided by the height of two sides
of a bevel. The triangle is similar to the original one

93 decision theorem 2, the two sides are proportional to each
other and the angles are equal, and the two triangles are
similar (SAS)

94 decision theorem 3, three sides corresponding proportional,
two triangle similarity (SSS)

The 95 theorem, if the right angle of a right triangle and the
right angled edge of another right triangle

The bevel is proportional to a right angle, so the two right
triangles are similar

96 property theorem 1 the ratio of the corresponding triangles,
the ratio of the corresponding line to the bisector of the
corresponding angle

The ratio is equal to the ratio

97 property theorem 2 the ratio of the perimeter of a similar
triangle is equal to the ratio of the similarity

98 property theorem 3 the ratio of the area of a similar triangle
is equal to the square of the similarity ratio

99 sine random acute value equal to its angle cosine value, any
acute angle cosine value equal to its

Coangle sine value

Tangent 100 any acute angle value equal to its complement of
the cotangent value, arbitrary cotangent value equal to its
angle

The tangent angle

The 101 circle is the set of points whose distance is equal to
the fixed length

The inner part of a 102 circle can be regarded as a set of points
whose distance is smaller than the radius

The outer part of a 103 circle can be regarded as a set of points
whose distance is greater than the radius

With 104 or so is equal to the radius of the circle

The distance from 105 to the point is equal to the locus of the
fixed point. The circle is fixed as the center of the circle
and the radius is fixed

The trajectory of a point equal to the distance between two
endpoints of a known line segment, the vertical bisector of a
line segment 106

The trajectory of a point equal to the distance between 107
sides of a known angle; the bisector of this angle

The trajectory of points from 108 to two parallel lines that
are parallel and equidistant from the two parallel lines

A straight line

The 109 theorem does not determine a circle at three points on
the same line.

110 the vertical diameter theorem is perpendicular to the
diameter of the chord, equal to the string, and the two arcs
of the string are equally divided

111 inference 1

The diameter of the chord (not the diameter) is perpendicular
to the string and the two arcs of the string are equally divided

The vertical bisector of the chord passes through the center
of the circle and divides the two arcs of the string equally

Equal to the diameter of an arc to which the chord is right,
vertically equal to the chord, and equal to the other arc of
the string

112 infer that the arc of the two parallel strings of the 2
circle is equal

The 113 circle is a central symmetrical figure centered on the
center of the circle

114 theorems in the same circle or congruent circles, arc equal
central angle of, the chords are equal,

The chord distances of the pairs of strings are equal

In the 115 round or round deduction, if the two central angle,
two arcs, two strings or two string string

There is a set of equal amounts in the center of the pitch, and
the rest of them are equal

The 116 theorem, the circumference of a pair of arcs is equal
to half the angle of the center of the circle it is centered
on

117 corollary 1 with arc or arc on the circle with equal angles;
or circle, equal circumferential angle

The arcs are equal

118 infer that the 2 circle (or diameter) is the right angle
of the circle; the circle of 90 degrees is the right chord

Diameter

119 inference 3 if the center line on one side of the triangle
equals half of the side, then the triangle is...

Right triangle

Complementary diagonal inscribed quadrilateral 120 circle
theorem, and any one of the corners are equal to it

horn

121 lines L and O intersect, d < R

The L and O d=r tangent line

The linear L and O from D > R

122 the judgment theorem of tangents follows the outer edge of
the radius and the straight line perpendicular to the radius
is the circle cut

Line

123 the nature of the tangent theorem; the tangent of the circle
is perpendicular to the radius of the tangent point

124 inference 1 the straight line passing through the center
of the circle and perpendicular to the tangent must pass through
the point of tangency

125 inference 2 the straight line passing through the point of
tangency and perpendicular to the tangent must pass through the
center of the circle

126 the long tangent theorem, the two tangents that draw the
circle from a point outside the circle, their tangents are equal,
the center of the circle and

The connection of this point divides the angle between the two
tangents

The two sets of 127 sides of a circumscribed quadrilateral and
equal

The 128 angle is equal to the circumference of the clamping
angle theorem of arc angle

129 that if the two angle between the arc are equal, then the
two angle is equal

The two intersecting string in the circle of 130 intersecting
chord theorem, the product of the two lines divided by the
intersection point is equal to the product of the same length

131 it is deduced that if the chord is perpendicular to the
diameter, then half of the string is the two line of its diameter

The ratio of mean

132 the cutting line theorem follows the tangent and secant of
a circle from a point outside the circle. The tangent length
is the point to the Secant and the circle

The two lines long term of proportion intersection

133 the two secant of a circle from a point outside the circle,
which is two of the intersection of each Secant and the circle

The product of a line segment is equal

134 If the two circles are tangent, then the point of tangency
must be on the center line

135, two, D, R+r, two, d=R+r, two, D, R-r, R+r (R > R)

Two circle inscribed d=R-r (R > R). The two circle contains d
< R-r (R > R)

A common chord in which 136 lines of two intersecting circles
are vertically divided into two equal circles

Divide the circle into 137 theorems of n (n = 3):

The connecting points of the polygon in turn is the circle
inscribed regular n polygon.

After all the points are tangent to a circle, the intersection
adjacent vertex tangent polygon is the circle

The circumscribed positive n edge

138 any theorem polygon has a circumscribed circle and a circle,
these two circles are concentric

Each corner 139 regular n polygon is equal to (n-2) * 180 degrees
n

The 140 theorem is the radius and the edge distance of the
positive n edge. The positive n edge is divided into 2n
congruent right triangle

141, the area of the positive n edge is Sn=pnrn 2 P, which
represents the perimeter of the positive n edge

The 142 is the triangle area root 3A 4 a side said

143 If there is an angle of K positive n edges around a vertex,
the sum of these angles should be 360 degrees due to

This k * (n-2) 180 deg n=360 is converted to (n-2) (K-2) =4

The 144 arc length formula: L=n was R 180

The 145 sector area formula: S sector =n Wu R^2 360=LR 2

146 inside length, =d- (R-r), grandfather tangent length = d-
(R+r)

Utilities: common mathematical formulas

Formula, formula, formula, expression

Multiplication and factorization, a2-b2= (a+b) (a-b), a3+b3=
(a+b) (a2-ab+b2)

A3-b3= (a-b (a2+ab+b2))

The triangle inequality is less than or equal to |a|+|b| less
than or equal to |a|+|b| |a-b| |a+b| |a| = b<=>-b = a = b

|a-b| = |a|-|b| -|a| = a = |a|

-b+ have the solutions of quadratic equation with one unknown
of the (b2-4ac) 2a -b- (b2-4ac) 2a V

Relation between roots and coefficients X1+X2=-ba, X1*X2=ca
notes: the laws of Weber

Discriminant

B2-4ac=0 note: equations have two equal real roots

B2-4ac>0 note: the equation has two unequal real roots

B2-4ac<0 note: the equation has no real roots and has conjugate
complex roots

Trigonometric function formula

The horns and formula

Sin (A+B) =sinAcosB+cosAsinB sin (A-B) =sinAcosB-sinBcosA

Cos (A+B) =cosAcosB- sinAsinB cos (A-B) =cosAcosB+sinAsinB

Tan (A+B) = (tanA+tanB) (1-tanAtanB) Tan (A-B) = (tanA-tanB)
(1+tanAtanB)

CTG (A+B) = (ctgActgB-1) (ctgB+ctgA) CTG (A-B) = (ctgActgB+1)
(ctgB-ctgA)

Double angle formula

Tan2A=2tanA (1-tan2A) ctg2A= (ctg2A-1) 2ctga

Cos2a=cos2a-sin2a=2cos2a-1=1-2sin2a

Half angle formula

Sin (A2) = V ((1-cosA) 2) sin (A2) = V ((1-cosA) 2)

Cos (A2) = V ((1+cosA) 2) cos (A2) = V ((1+cosA) 2)

Tan (A2) = V ((1-cosA) ((1+cosA)) Tan (A2) = V ((1-cosA)
((1+cosA))

CTG (A2) = V ((1+cosA) ((1-cosA)) CTG (A2) = V ((1+cosA)
((1-cosA))

Sum and difference product

2sinAcosB=sin (A+B), +sin (A-B), 2cosAsinB=sin (A+B), -sin
(A-B)

2cosAcosB=cos (A+B), -sin (A-B), -2sinAsinB=cos (A+B), -cos
(A-B)

SinA+sinB=2sin ((A+B) 2) cos ((A-B) 2

CosA+cosB=2cos ((A+B) 2) sin ((A-B) 2)

TanA+tanB=sin (A+B) cosAcosB tanA-tanB=sin (A-B) cosAcosB

CtgA+ctgBsin (A+B) sinAsinB - ctgA+ctgBsin (A+B) sinAsinB

Certain sequences, first n items, and

1+2+3+4+5+6+7+8+9+... +n=n (n+1) 2 1+3+5+7+9+11+13+15+... +
(2n-1) =n2

2+4+6+8+10+12+14+... + (2n) =n (n+1) 13+23+33+43+53+63+...
N3=n2 (n+1) 24

12+22+32+42+52+62+72+82+... +n2=n (n+1) (2n+1) 6

1*2+2*3+3*4+4*5+5*6+6*7+... +n (n+1), =n (n+1) (n+2), 3

Note: the sine theorem of asinA=bsinB=csinC=2R where R is
the radius of circumcircle of triangle

Cosine theorem b2=a2+c2-2accosB note: the angle B is the angle
between the edge a and the edge C

The standard equation of the circle (x-a), 2+ (y-b) 2=r2 note:
(a, b) is the coordinate of the center of the circle

General equation of circle x2+y2+Dx+Ey+F=0 note: D2+E2-4F>0

Parabolic standard equation y2=2px, y2=-2px, x2=2py, x2=-2py

The area of the straight prism is S=c*h, the area of the oblique
prism is S=c'*h, and the area of the right pyramid is S=12c*h'

A regular prismoid lateral area (c+c') S=12 H' S=12 (c+c')
side cone area l=pi (R+r) l

The surface area of the ball is S=4pi*r2, and the area of the
cylinder is S=c*h=2pi*h

Cone side area S=12*c*l=pi*r*l

The arc length formula l=a*r, a is the radian number of the
center angle, r>0 sector formula s=12*l*r

Cone volume formula V=13*S*H cone volume formula V=13*pi*r2h

Note: the oblique prism volume V=S'L, S'is a straight section
area, L is the long side edge

Cylindrical volume formula V=s*h cylinder V=pi*r2h

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